  Get free ebooK with 50 must do coding Question for Product Based Companies solved
Fill the details & get ebook over email  Thank You!
We have sent the Ebook on 50 Must Do Coding Questions for Product Based Companies Solved over your email. All the best!

Last Updated on March 25, 2022 by Ria Pathak Hard.

### Problem Statement :

Reverse a linked list from position M to N. Do it in-place and in one-pass.

#### Example:

``````Given 1−>2−>3−>4−>5−>NULL,
M=1 and N=3,
Output:  3−>2−>1−>4−>5−>NULL.``````

See original problem statement here

### EXPLANATION:

Since we have to reverse a part of the given linked list obviously we need the concept of reversing the linked list. We need to find the mth node and pass it to the reverse function (which will reverse the given part). But, before passing the mth node we need to traverse to the nth node and cut its link with (n+1)th node if present.

Also we have to save the (m-1) node and also (n+1)th node address so that we can link the reversed part of the linked list again with the original linked list.

There will be four variables.
`Prev` → for storing the previous node, i.e. (m-1)th node.

`Start` → for storing the starting(mth) node of reversal.

`End` → for storing the ending node(nth) of reversal.

`Next` → for storing the next node, i.e. (n+1)th node.

Now, we will pass Start to the reverse function and then will attach the reversed part with Start and End to get the reversed linked list.

### SOLUTIONS:

``` #include <stdio.h>
#include<stdlib.h>
struct Node {
int data;
struct Node* next;
};
{
struct Node* prev = NULL;

while (curr) {
struct Node* next = curr->next;
curr->next = prev;
prev = curr;
curr = next;
}
return prev;
}
struct Node* reverseBetween(struct Node* head, int m, int n)
{
if (m == n)
struct Node* revs = NULL, *revs_prev = NULL;
struct Node* revend = NULL, *revend_next = NULL;
int i = 1;
while (curr && i <= n) {
if (i < m)
revs_prev = curr;

if (i == m)
revs = curr;

if (i == n) {
revend = curr;
revend_next = curr->next;
}

curr = curr->next;
i++;
}
revend->next = NULL;
revend = reverse(revs);
if (revs_prev)
revs_prev->next = revend;
else

revs->next = revend_next;
}

{
}
printf("\n");
}
void push(struct Node** head_ref, int new_data)
{
struct Node* new_node ;
new_node=(struct Node *)malloc(sizeof(struct Node));
new_node->data = new_data;
}
int main()
{ int k;scanf("%d",&k);
int x[k];
for(int i=0;i<k;i++)
scanf("%d",&x[i]);
for(int i=k-1;i>=0;i--)
{
}
int m,n;scanf("%d%d",&m,&n);
return 0;
}
```
``` #include <bits/stdc++.h>
using namespace std;
struct Node {
int data;
struct Node* next;
};
{
struct Node* prev = NULL;

while (curr) {
struct Node* next = curr->next;
curr->next = prev;
prev = curr;
curr = next;
}
return prev;
}
Node* reverseBetween(Node* head, int m, int n)
{
if (m == n)
Node* revs = NULL, *revs_prev = NULL;
Node* revend = NULL, *revend_next = NULL;
int i = 1;
while (curr && i <= n) {
if (i < m)
revs_prev = curr;

if (i == m)
revs = curr;

if (i == n) {
revend = curr;
revend_next = curr->next;
}

curr = curr->next;
i++;
}
revend->next = NULL;
revend = reverse(revs);
if (revs_prev)
revs_prev->next = revend;
else

revs->next = revend_next;
}

{
}
printf("\n");
}
void push(struct Node** head_ref, int new_data)
{
struct Node* new_node = new Node;
new_node->data = new_data;
}
int main()
{ int k;cin>>k;
int x[k];
for(int i=0;i<k;i++)
cin>>x[i];
for(int i=k-1;i>=0;i--)
{
}
int m,n;cin>>m>>n;
return 0;
}
```
```class Solution {
public:
ListNode *reverseBetween(ListNode *head, int m, int n) {
for(auto i = 0 ; i < m-1 ; i++){
prev = prev->next;
}
ListNode* const reversedPrev = prev;
//position m
prev = prev->next;
ListNode* cur = prev->next;
for(auto i = m ; i < n ; i++){
prev->next = cur->next;
cur->next = reversedPrev->next;
reversedPrev->next = cur;
cur = prev->next;
}
}
};
```
```class Node:

def __init__(self, data):
self.data = data
self.next = None

def __init__(self):

def reverse(self):
prev = None
while(current is not None):
next = current.next
current.next = prev
prev = current
current = next

def push(self, new_data):
new_node = Node(new_data)

def printList(self):
while(temp):
print(temp.data, end=" ")
temp = temp.next

llist.push(20)
llist.push(4)
llist.push(15)
llist.push(85)