### Introduction

In this blog we will learn to merge sort using a linked list in C. Sorting is an essential part of data structures. Before diving into the concepts of merge sort, let’s understand the basics first.

### Problem Statement of merge sort using a linked list in C

According to the problem statement, we are given a singly linked list, and we need to sort this singly linked list using merge sort.

### Merge Sort

Merge sort is a divide and conquer algorithm.

- It is a recursive algorithm.
- In merge sort, we have to divide the container (container can be an array, list, etc.) into two halves, then we will call merge sort recursively on the two halves.
- These two merge sort calls return a sorted container, and we then merge these sorted containers in such a way that the whole container remains sorted.
- Have a look at the below image to see in a nutshell how merge sort works.

Now, we have a brief understanding of the merge sort algorithm. Let’s learn how to apply merge sort on a singly linked list.

In the case of a linked list, we will recursively divide the list into two sub-lists at each step till the list size is reduced to one and while backtracking from the recursive call, we have two sorted lists, which will be merged together into a single list by merge operation in linear time.

Now we will look at the approach and algorithm, to know how to apply merge sort on a singly linked list.

### Approach and Algorithm of merge sort using a linked list in C

- If the
**head**of the linked list is NULL or**(head→ next == NULL)**, it shows that our linked list is of size 1 or 0 and a linked list of size zero or one is already sorted. So, Don’t do anything, just return**head**. - If the linked list is of
**size > 1**then first find the**middle**of the linked list. - For finding middle node, use
**slow and fast pointer method**. - In this method, we take two pointers
**slow**and**fast**and initialize them with**head**. - Then we move the
**slow pointer**by one node and**fast pointer**by 2 nodes until the fast pointer reaches the tail of the list. - And when the
**fast pointer**reaches the**tail**, the**slow pointer**will be at the**middle**of the linked list. - The only reason why
**slow pointer**will be at the**middle**of the list, when**fast**reaches**tail**is because the**slow pointer is moving with half the speed of fast pointer**and when the fast pointer has traversed the complete list till then the slow pointer will have only traversed half the list, so that’s why slow pointer will be at the middle of the list. - Now, store
**slow → next**in a pointer named**afterMiddle**and assign**slow → next = NULL**. - Recursively call
**mergeSort()**on both**left and right sub-linked list**and store the new head of the left and right linked list in pointer variable**part1**and**part2**. - When the recursive call on the left and right sub-list returns, merge the two linked lists returned by recursive calls (remember that the recursive call will return the sorted lists).
- Return the final head of the merged linked list.

#### Merging two sorted linked list Algorithm:

When the two recursive calls will return the two sorted lists, then we will merge that sorted list into a single list using these below steps.

- Initialize two pointer variables named
**curr1**and**curr2**with left sorted sub-list and right sorted sub-list. - Initialize two pointer variable named
**si**and**ei**with NULL; these two pointer variables are the**head**and**tail**of the final sorted linked list. - If the data of
**curr1**is less than the data of**curr2**, then, store**curr1**in next of**ei**& move**curr1**to the next of**curr1**. - Else, if the data of
**curr2**is less than the data of**curr1**, then store**curr2**in next of**ei**& move**curr2**to the next of**curr2**. - Repeat steps 3 and 4 until either of the
**curr1**or**curr2**is not equal to NULL. - Now add any remaining nodes of the first or the second linked list to the merged linked list.
- Return the head of the merged sorted linked list containing all the nodes of the two sorted sub-lists.

### Dry Run of merge sort using a linked list in C

### Code Implementation of merge sort using a linked list in C

#include#include /* Link list node */ struct Node { int data; struct Node* next; }; /* function prototypes */ struct Node* SortedMerge(struct Node* a, struct Node* b); void middle(struct Node* source, struct Node** frontRef, struct Node** backRef); /* sorts the linked list by changing links */ void MergeSort(struct Node** headRef){ struct Node* head = *headRef; struct Node* a; struct Node* b; /* Base case -- length 0 or 1 */ if ((head == NULL) || (head->next == NULL)) { return; } middle(head, &a, &b); MergeSort(&a); MergeSort(&b); *headRef = SortedMerge(a, b); } struct Node* SortedMerge(struct Node* a, struct Node* b) { struct Node* result = NULL; /* Base cases */ if (a == NULL) return (b); else if (b == NULL) return (a); if (a->data <= b->data) { result = a; result->next = SortedMerge(a->next, b); } else { result = b; result->next = SortedMerge(a, b->next); } return (result); } /* This function splits the list from the middle */ /* After splitting Original list converts into two list first list -> head to the node previous of middle and second list -> middle to end */ void middle(struct Node* source, struct Node** frontRef, struct Node** backRef) { struct Node* fast; struct Node* slow; slow = source; fast = source->next; /* Advance 'fast' two nodes, and advance 'slow' one node */ while (fast != NULL) { fast = fast->next; if (fast != NULL) { slow = slow->next; fast = fast->next; } } /* 'slow' is before the midpoint in the list, so split it in two at that point. */ *frontRef = source; *backRef = slow->next; slow->next = NULL; } /* Function to print linked list */ void printList(struct Node* node){ while (node != NULL) { printf("%d ", node->data); node = node->next; } } /* Function to insert a node at the beginning of the list */ void push(struct Node** head_ref, int new_data){ /* allocate node */ struct Node* new_node = (struct Node*)malloc(sizeof(struct Node)); /* assign the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head pointer to point to the new node */ (*head_ref) = new_node; } int main(){ struct Node* res = NULL; struct Node* a = NULL; /* Let's create a new linked lists */ /* a: 8->9->5->3->2 */ push(&a, 2); push(&a, 3); push(&a, 5); push(&a, 9); push(&a, 8); printf("Linked List before sorting: \n"); printList(a); printf("\n"); /* Sort the Linked List */ MergeSort(&a); printf("Linked List after Sorting: \n"); printList(a); getchar(); return 0; }

#### Output

Linked List before sorting

8 9 5 3 2

Linked List after sorting

2 3 5 8 9

**Time Complexity of merge sort using a linked list in C:** O(n*log n)

So, In this article, we have learned how to apply for the merge sort

program in C. We discussed the merge sort algorithm in detail we also took a look at the time and space complexity of merge sort for linked list in detail. This is an important problem when it comes to coding interviews. If you want to practice more questions on linked lists feel free to solve them at Prepbytes (Linked Lists).

## FAQs related to merge sort using a linked list in C

- What is the merge sort algorithm?
- Does merge sort require extra space?
- What is the sorting algorithm in C?
- Bubble sort
- Selection sort
- Insertion sort
- Quick sort
- Merge sort

The merge sort algorithm is a divide-and-conquer algorithm. Merge sort divides the data into equal parts repeatedly until the element becomes single and merges back these elements in such a way that the data becomes sorted.

Yes, merge sort requires O(logn) extra space for linked lists.

C language provides five sorting algorithms:

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